Tìm tổng các hệ số của đa thức P(x)=3x^5+2x^2+(x^2-x)^2016+1
Giúp mình nhé
Anh TrúcTeacher
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
P(x)=3x^5+2x^2+(x^2-x)^2016+1
P(x)=3x^5+2x^2+x^4032-x^2016+1
P(x)=(1)x^4032-(1)x^2016+(3)x^5+(2)x^2+(1)
Tổng hệ số: 1+1+3+1=6
Hok tốt^^