tìm x đi cu $\frac{11}{x+3}$ = $\frac{33}{2x+17}$ $\frac{3x-2}{5}$ = $\frac{5x-1}{7}$

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tìm x đi cu
$\frac{11}{x+3}$ = $\frac{33}{2x+17}$
$\frac{3x-2}{5}$ = $\frac{5x-1}{7}$

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    `text{Tỉ lệ thức:}`

    `ad=bc=>a/b=c/d`

    `1.`

    `11/(x+3) = 33/(2x+17)`

    `=>33(x+3)=11(2x+17)`

    `33x+99 = 22x+187`

    11x=88`

    `x=8`

    Vậy `x=8`

    `2.`

    `(3x-2)/5=(5x-1)/7`

    `=>7(3x-2)=5(5x-1)`

    `21x-14=25x-5`

    `4x=-9`

    `x=-9/4`

    Vậy `x=-9/4`

    `@Dawn,byet`

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