nốt câu7giúp bé vs ah

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nốt câu7giúp bé vs ah

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    Đáp án:

     

    Giải thích các bước giải:

    `n_(KClO_3)= (12,25)/( 122,5) = 0,1 (mol) `

     `2KClO_3 ` $\xrightarrow[a]{b}$ `2KCl + 3O_2 `

    `0,1 -> 0,1 -> 0,15 (mol) `

    Ta có : `H = (n_tt)/(n_lt) * 100% = 80% ` 

    `-> n_(KClO_3)tt = 0,08 (mol) `

    `-> n_(O_2)` thực tế : `0,08 *3 /2 = 0,12 (mol) `

    `-> V_(O_2) = 0,12 * 24,79 = 2,9748L `

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