giúp mình nhanh với ạ

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giúp mình nhanh với ạ

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    #cb.

    Ta có:

    `6x=4y=z`

    `=>(6x)/12=(4y)/12=z/12`

    `=>x/2=y/3=z/12`

    Áp dụng tc dãy tỉ số bằng nhau, ta có:

    `x/2=y/3=z/12=(2x)/4=(3y)/9=z/12=(2x-3y+z)/(4-9+12)=42/7=6`

    Vì `x/2=6=>x=12`

    `y/3=6=>y=18`

    `z/12=6=>z=72`

    Vạy `x=12`;`y=18` và `z=72`

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