câu 7 thôi ah hhhhhhhhhhhhhhhh

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câu 7 thôi ah
hhhhhhhhhhhhhhhh

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    $\#duaconngoaihanhlang$

    `n_{KClO_3}=(12,25)/(122,5)=0,1(mol)`

    `PTHH:`

    `2KClO_3` $\xrightarrow{t^o}$ `2KCl+3O_2`

    Theo pt: `n_{O_2}=3/2.n_{KClO_3}=0,15(mol)`

    Mà `H\%=80\%` 

    `=>n_{O_2\text{ (tạo ra)}}=0,15.80\%=0,12(mol)`

    `=>V_{O_2}=0,12.24,79=2,9748(L)`

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